Question

Imi puteti explica si mie cum se rezolva acest exercitiu ? Multumesc!

Answer 1

$i^2 = -1 \quad (identitate)$
$(a-b)^2 = a^2-2\cdot a\cdot b + b^2$

$z=1- i \Big|^2 \Rightarrow z^2 = (1-i)^2 \Rightarrow z^2 = 1^2-2\cdot i + i^2 \Rightarrow z^2 = 1 - 2i-1 \Rightarrow \\ \\ \Rightarrow \boxed{ z^2 = -2i}$

Answer 2

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