Question

imi rezolva cineva pls exercițiul:


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Answer 1

[5×(5×5+5:5)-a]:10=3

[5×(25+1)-a]:10=3

(5×26-a):10=3

(130-a):10=3

130-a=10×3

130-a=30

a=130-30

a=100

Answer 2

$\bf [5\cdot(5\cdot5+5:5)-a]:10=3$

$\bf [5\cdot(25+1)-a]:10=3\:\:\:|\cdot10\:\text{\it inmultim toata relatia cu 10}$

$\bf 5\cdot 26 -a =30$

$\bf 130 -a =30\:\:\:\:\:\:|+a$

$\bf 130 -a+a =30 +a$

$\bf 130 =30 +a$

$\bf a =130 -30$

$\boxed{\bf a =100}$