Question

îmi rezolvati si mie acest exercitiu .dau coroana

Answer 1

(3/2√3-15/5√3+9/3√3)-(12/4√3-45/5√3+24/8√3)
amplifici cu √3 la fiecare si obti 
3/2√3=3√3/6=√3/2
15/5√3=15√3/15=√3
9/3√3=9√3/9=√3
12/4√3=12√3/12=√3
45/5√3=45√3/15=3√3
24/8√3=24√3/24=√3
astfel exercitiul devine
(√3/2-√3+√3)-(√3+3√3+√3)=√3/2-5√3
amplifici pe 5√3 cu 2
(√3-10√3)/2=-9√3/2