Question

Îmi trebuie urgent am teza!!!

Answer 1

"V"=radical

V(x+3)=-2, imposibil, radicalul este mereu >=0

V(x^2 -7)=3, ridicam la patrat
x^2 -7=9
x^2=16
x=+/-4

V(6-x)=x, conditie esentiala x>=0
Ridicam la patrat
6-x=x^2
x^2 +x-6=0
(x-2)(x+3)=0
x=+2 sau x=-3, dar x>=0, rezulta
       x=+2

  3
V(2x+3)=-3, ridicam la cub
2x+3=-27
2x=-30
x=-15

V(x^2 -1)=x-3
Conditii existentiale:x-3>=0 si x^2 -1>=0, adica x>=3 si x=R-(-1;+1), adica
x>=3 si atat.

Ridicam la patrat:
x^2-1=x^2 -6x+9
6x=10
x=10/6
x=5/3 <3, deci nu e solutie

Ecuatia nu are solutii reale.