Question

îmo vine sa ma rogg....​

Answer 1

a) N(1) =$\sqrt{3^{2}+8\cdot3+16 }$=$\sqrt{49}$=7 nr natural

b) N(n)=$\sqrt{(3^x)^2+2\cdot3^x\cdot4+4^2}$ =$\sqrt{(3^x+4)^2}$=$3^x$+4 numar rational.

Coroana, te rog!