Question

impare nr 473 in parti direct proportionale cu nr 7 11 si 25

Answer 1

{ a,b,c } d.p { 7,11,25 }
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a + b + c = 473
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a  / 7 = b / 11 = c / 25 = K

a / 7 = K => a = 7 K

b / 11 = K => b = 11 K

c / 25 = K => c = 25 K

7 K + 11 K + 25 K = 473
18 K + 25 K = 473
43 K = 473
K = 473 : 43
K = 11

a = 11 x 7 = 77

b = 11 x 11 = 121

c = 11 x 25 = 275

Answer 2

 {a,b,c} d.p.  cu {7,11,25}

a/7 = b/11 = c/25 = k⇒ a = 7k,  b =11k,   c = 25k,

7k + 11k + 25k = 473

 43 k = 473⇒ k =11


a = 7k= 7 ×11 =77
b =11 k=11 × 11 =121
c = 25 k = 25 ×11 =275

cele 3 numere sunt : 77, 121 si 275