Question

impart la7suma a patru numere consecutive si obtincatul 12si restul6. aflati nr.

Answer 1

S=suma
S:7=12 rest 6
S=7x12+6
S=90
A+b+c+d=90
B=a+1
C=a+2
D=a+3
A+a+1+a+2+a+3=90
4xa=84
A=21
B=22
C=23
D=24

Answer 2

(x + x + 1 + x + 2 + x + 3) : 4 = 12 r 6
=> x + x + 1 + x + 2 + x + 3 = 12*4 + 6 = 48 + 6 = 54
=> 4x + 6 = 54
=> 4x = 54 - 6 = 48
=> x = 48 : 4 = 12