Question

Imparte numarul 462 in parti direct proportionale cu numerele 3;7;11.

Answer 1

a+b+c=462

{a,b,c} d.p. {3;7;11}

$\frac{a}{3} = \frac{b}{7} = \frac{c}{11} =k$

a=3k
b=7k
c=11k

a+b+c=462⇒3k+7k+11k=462⇒21k=462⇒k=22

a=3k⇒a=22·3⇒a=66
b=7k⇒b=22·7⇒b=154
c=11k⇒c=22·11⇒c=242

Answer 2

a+b+c=462
a,b,c direct proportioate cu :3,7,11.

a=3K
    
b=7K
 
c=11K
      
a+b+c=462
a=3K
b=7K     ⇒3K+7K+11K=462
c=11K    ⇒21K=462
               ⇒K=22
a=3×22
a=66

b=22×7
b=154

c=22×11
c=242

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