Question

Imparte suprafata 200 ha in 5 parti direct proportionale cu 4,3,10,6,respectiv 2

Answer 1

$\displaystyle\\ k = \frac{200}{4+3+10+6+2}= \frac{200}{25}= \boxed{8}\\\\ p1=4k = 4\times 8 = \boxed{\bf32~ ha}\\ p2=3k=3\times 8 = \boxed{\bf24~ ha}\\ p3=10k =10\times 8 = \boxed{\bf80~ ha}\\ p4=6k =6\times 8 = \boxed{\bf48~ ha}\\ p5=2k =2\times 8 = \boxed{\bf16~ ha}\\\\ V\!\!:~~32+24+80+48+16=200$

Answer 2

a+b+c+d+e=200, a/4=b/3=c/10=d/6=e/2, b=3a/4, c=10a/4, d=6a/4, e=2a/4

inlocuim b, c, d, e in prima ecuatie, a+3a/4+10a/4+6a/4+2a/4=200, Ix4

4a+3a+10a+6a+2a=800, 25a=800, a=800/25=32, b=32x3/4=24, c=32x10/4=80,

d=32x6/4=48, e=32x2/4=16, verificare 32+24+80+48+16=200 ha