Question

impartim numarul 142 in parti invers proportionale cu numerele 3,5,7

Answer 1

x + y + z = 142

3 x = 5 y = 7 z = k

3 x = k => x = k / 3

5 y = k => y = k / 5

7 z = k => z = k / 7

k / 3 + k / 5 + k / 7 = 142

35 k / 105 + 21 k / 105 + 15 k / 105 = 142

71 k / 105 = 142 / 1

71 k = 105 × 142

71 k = 14910

k = 14910 / 71

k = 210

x = 210 / 3 = 70

y = 210 / 5 = 42

z = 210 / 7 = 30