Question

impartind 6 numere naturale consecutive la 6 se obtine mereu catul 5 . Aflati numerele

Answer 1

a + a + 1 + a + 2 + a + 3 + a + 4 + a + 5 = 6a + 15
(6a + 15) : 6 = 5
6a + 15 = 30
6a = 30 - 15
6a = 15
a = 15/6
a = 3/2
a + 1 = 3/2 + 1 = 5/2
a + 2 = 3/2 + 2 = 7/2
a + 3 = 3/2 + 3 = 9/2
a + 4 = 3/2 + 4 = 11/2
a + 5 = 3/2 + 5 = 13/2

Answer 2

x : 6 = 5 (resturile posibile 0;1;2;3;4;5;)
↓
x = {30 ; 31; 32 ; 33 ; 34 ; 35 } !

Verificare: 30:6=5 ; 31:6=5 (rest 1) ; 32:6=5 (rest 2) ; 
                 33:6=5 (rest 3) ; 34:6=5 (rest 4) ;
                 35:6=5 (rest 5) ;