Question

 impartind doua nr natureale obtinem catul 12 si restul 11 adunand deimpartitul impartitorulsi catul obtinem205 care sunt nr

Answer 1

a+b=205
a:b=12 rest 11
12b+11+b+12=205
13 b=205-11-12
13 b=182
b=182:13=14
a=12b+11=12x14+11=168+11=179



179+14+12=205
179:14=12 rest 11

Answer 2

a : b =12 r 11
a=bx12+11
a+b+12= 205
bx12+11+b+12=205
13b+23=205
13b=205-23
b=182:13
b=14
a+14+12=205
a+26=205
a=205-26
a=179
v) 179:14=12r11