Question

impartind nr x la y obtinem catul 3 si restul 19

1)Calculati 2x-6y+3;
2)Aratati ca x+y>95​

Answer 1

Răspuns:

Explicație pas cu pas:

x=3·y+19, deci x-3y=19

1)Calculati 2x-6y+3=2·(x-3y)+3=2·19+3=38+3=41

2) rest < impartitor, deci y>19

3·y>3·19, ⇒3·y > 57

x=3y+19, deci 3y+19>57+19, deci x>76

Deci x+y>76+19⇒   x+y>95

Answer 2

Răspuns:

X = 3y + 19 ==> X - 3y = 19

1) 2X - 6y + 3 = 2 × (x - 3y) + 3 = 2 × 19 + 3 = 38 + 3 = 41

2) X × y > 95

formula : rest < impartitor ==> y > 19

3y > 3 × 19 ==> 3y = 57

X = 3y + 19 ==> 3y + 19 > 57 + 19 ==> X > 76

X + y > 76 + 19 = X + y > 95

> = mai mare