Question

impartind sase numere naturale consecutive la 6 se obtin mereucatul5.determinati cele sase numere

Answer 1

Cele sase nr consecutive sunt notate: a, a+1,a+2,a+3,a+4,a+5
  a
----- = 5 => a=30
  6

30+1
------ = 5 rest 1
  6

.............

30+5
------ = 5 rest 5
  6