Question

Impartind suma a 3 numere naturale consecutive la 7 obinem catul 13 si restul 5. Aflati cele 3 numeree.

Answer 1

(n+n+1+n+2):7=13rest5, 3n+3=7*13+5 (teorema impartirii cu rest)

3n=91+5-3=93, n=93/3=31,

numerele sunt 31, 32,33,  

verificare : 31+32+33=96, 96/7=13rest5