Question

impartind suma a trei nr naturale consecutive la 7 obtinem catul 13 si restul 5 . aflati celee 3 nr

Answer 1

S:7=13,5
S=7*13+5
S=91+5
S=96

a
a+1
a+2
=======(+)
3a+3=96
3a=93
a=93:3
a=31

NR sunt 31 32 33

Answer 2

[a+b+c]/7=13 rest 5;
⇒[a+a+1+a+2]=7·13+5
⇒[3a+3]=91+5
⇒3a+3=96⇒3a=93⇒a=31;
⇒b=32;
⇒c=33;