Question

impartind.suma.a.trei.numere.consecutive.la.8.obtin.catul.108.si.restul..3.care.sunt.numerele?

Answer 1

[a+(a+1)+(a+2)]:8 = 108 rest 3
3×a+3 = 8×108+3
3×a+3 = 864+3
3×a+3 = 867
3×a = 867-3
3×a = 864
a = 288:3
a = 288
(a+1 )= 289
(a+2) = 290

Verificare:
288+289+290 = 867
867:8 = 108 rest 3

Numerele consecutive sunt:
288; 289; 290