Question

impartirea radicalilor
Calculati:
1 (10 radical15) : (2 radical 5) =
2 (radical 14) : (radical 7)=
3 ( - radical 10): (- radical 5)=
4 (6 radical 21) : ( 2 radical 7)=
5 (- 2 radical 5) : ( 2 radical 5)=
6 ( 11 radical 5) : 11=
7 (7 radical 3) : radical 3 =
8 (- 6 radical 6 ) : ( 2 radical 2)=
9 ( 4 radical 35) : (2 radical 5) =​​

Answer 1

Răspuns:

Explicație pas cu pas:

1) 10√15 : 2√5 = (10:2) · √(15:5) = 5√3

2) √14 : √7 = √(14:7) = √2

3) (-√10) : (-√5) = √(10:5) = √2

4) 6√21 : 2√7 = (6:2)·√(21:7) = 3√3

5) (-2√5) : 2√5 = (-2:2)·√(5:5) = -1·√1 = -1

6) 11√5 : 11 = (11:11)·√5 = √5

7) 7√3 : √3 = 7·√(3:3) = 7·√1 = 7

8) -6√6 : 2√2 = (-6:2)·√(6:2) = -3√3

9) 4√35 : 2√5 = (4:2)·√(35:5) = 2√7