Question

impartiti nr 145 in parti invers proportionale cu nr 1 pe 2 , 0,4 , 3

Answer 1

1/2=0,5
0,5x=k   x=2k
0,4y=k   y=2,5k
3z=k      z=k/3
2k+2,5k+k/3=145
6k+7,5k+k=435
14,5k=435
k=30
x=2*30=60
y=2,5*30=75
z=30/3=10