Question

Impartiti nr 15 in parti direct proportionale cu numerele 2 si 3.

Answer 1

a+b=15

{a,b}dp{2,3}=>a supra 2=b supra 3

egalam cu k=>a=2k si b=3k

2k+3k=15

5k=15

k=3=>a=3*2=6

b=3*3=9

Answer 2

{x;y}d.p.{2;3}
x/2=y/3=k
x=2k
y=3k
x+y=15
2k+3k=15
5k=15
k=3
x=6
y=9
(Nr sunt 6 si 9)