Question

impartiti nr 192 in parti invers proportionale cu nrr 3 si 5
impartiti nr 270 in parti invers proportionale cu nr 2 si 7 va rog frumoa rezolvarea

Answer 1

1) Fie 192=a+b
3*a=5*b
b=3*a/5=0,6*a
a+0,6*a=192
1,6*a=192
a=120
b=72
2) Fie 270=a+b
2*a=7*b
a=7*b/2=3,5*b
3,5*b+b=270
4,5*b=270
b=60
a=210