Question

Impartiti nr 40 in parti invers proportionale cu 0,2; 0,5; 0,(3)

Answer 1

x/(1/0,2)=k      x=k/0,2=5k
y/(1/0,5)=k      y=k/0,5=2k
z/[1/0,(3)]=k    z=3k
5k+2k+3k=40
10k=40
k=4
x=5*4=20
y=2*4=8
z=3*4=12