Question

IMPARTITI NR .420 IN PARTI INVERS PROPORTIONALECU 2,5,6. Multumesc anticipat!!

Answer 1

2x=5y=6z=k
x=k/2
y=k/5
z=k/6
x+y+z=420
k/2+k/5+k/6=420
13k/15=420
(15*13k)/(13*15)=15/13*420
(15*13k)(13/15)=(15*420)/13
k=(15*420)/13
k=6300/13

x=k/2    x=(6300/13)/2=3150/13
y=k/5    y=(6300/13)/5=1260/13
z=k/6     z=(6300/13)/6=1050/13