Question

impartiti nr 60 in parti direct proportionale cu 2 cu 3 si cu 5

Answer 1

a+b+c=60
{a, b, c} d.p. {2, 3, 5}
a/2=b/3=c/5=k
=> a=2k
=> b=3k
=> c=5k
2k+3k+5k=60
10k=60
k=6
a=2•6=12
b=3•6=18
c=5•6=30