Question

Impartiti nr 90 in mod invers proportional cu 2 3 6

Answer 1

[tex] Fie a,b,c numerele (a,b,c ) i.p ( 2,3,6 ) =) 2a = 3b = 6c = k a = k/2 b = k/3 c = k/6 a + b + c = k/2 + k/3 + k/6 = 90 3k/6 + 2k/6 + k/6 = 6 * 90 3k/6 + 2k/6 + k/6 = 540 k = 540 : 6 k = 90 Inlocuim in formulele de mai sus =) a = k/2 = 90/2 = 45 b = k/3 = 90/3 = 30 c = k/6 = 90/6 = 15 [/tex]

Answer 2

a/1/2=b/1/3=c/1/6=
=90/1/2+1/3+1/6
=90/1=90
a=90/2
a=45
b=90/3
b=30
c=90/6
c=15