Question

Împărțiți nr3804 in părți invers proporțională cu 0,(6);0,75;0,8;0,8(3)

Answer 1

0,(6)=6/9=2/3           
0,75=75/100=3/4
0,8=8/10=4/5
0,8(3)=(83-8)/90=75/90=5/6
x/[1/(2/3)]=k    2x/3=k    x=3k/2
y/[1/(3/4)]=k    3y/4=k    y=4k/3
z/[1/(4/5)]=k    4z/5=k    z=5k/4
t/[1/(5/6)]=k    5t/6=k     t=6k/5
x+y+z+t=3804
3k/2+4k/3+5k/4+6k/5=3804
90k+80k+75k+72k=228240
317k=228240
k=720
x=3k/2=3*720/2=1080
y=4k/3=4*720/3=960
z=5k/4=5*720/4=900
t=6k/5=6*720/5=864