Question

Impartiti numarul 106 in parti direct proportionale cu numerele 0,(3) ; 2 si 1,2.

Answer 1

0,(3)=3/9=1/3
x=k/3
y=2k
z=1,2k=12k/10=6k/5
x+y+x=106
k/3+2k+6k/5=106
5k+30k+18k=1590
53k=1590
k=30
x=30/3=10
y=2*30=60
z=6*30/5=36