Question

Impartiti numarul 106 in parti direct proportionale cu numerele 0,(3) ; 2 ; 1,2

Answer 1

0,(3)k=k/3
2k
1,2k
k/3+2k+1,2k=106
k+6k+3,6k=318
10,6k=318
k=30
numerele sunt
k/3=30/3=10
2k=2x30=60
1,2k=1,2x30=36