Question

Impartiti numarul 1440 in parti direct proportionale cu 3,11,2,8

Answer 1

Fie a,b,c,d partile direct prop cu nr 3,11,2,8
a+b+c+d=1440 
a/3=b/11=c/2=d/8=k
a=3k, b=11k, c=2k, d=8k
3k+11k+2k+8k=1440
24k=1440
k=1440/24=60
a=3*60=180
b=11*60=660
c=2*k=2*60=120
d=8*k=480