Question

impartiti numarul 145 in parti invers proportionale cu numerele 1/2, 0,4 si 3

Answer 1

1/2 · a = 4/10 · b = 3· c = k 
a = 2·k 
b=5k /2 
c = k/3 
a +b+c = 145 
2·k + 5k /2 + k /3 = 145   ; 12k + 15k + 2k = 145 · 6   ;  29k = 870 
k =870 : 29 = 30 
a = 2 ·30 = 60
b = 5·30 :2 = 75
c = 30/3 =10