Question

impartiti numarul 210 in parti direct proportionale cu numerele 8,9 si 13

Answer 1

{a,b,c} d.p. {8,9,13}
a+b+c=210
a/8=b/9=c/13=k
a/8=k => a=8k
b/9=k => b=9k
c/13=k => c=13k
8k+9k+13k = 210
30k=210
k= 210/30
k=7
a=8k =>a=8x7, a=56
b=9k =>b=9x7, b=63
c=13k =>c=13x7, c=91