Question

impartiti numarul 26 in parti direct proportionale cu 0,25 , 0,(3) , 0,5

Answer 1

a,b,c :partile
(a,b,c) d.p (0,25; 0,(3) ; 0,5)
a+b+c= 26
$\frac{a}{0,25}$ =$\frac{b}{0,(3)}$ = $\frac{c}{0,5}$
 0,25=$\frac{25}{100}$=$\frac{1}{4}$
0,(3)=$\frac{3}{9} = \frac{1}{3}$
0,5=$\frac{5}{10} = \frac{1}{2}$
[tex] \frac{a}{ \frac{1}{4} }= \frac{b}{ \frac{1}{3} }= \frac{c}{ \frac{1}{2} } = \frac{a+b+c}{ \frac{1}{4}+ \frac{1}{3}+ \frac{1}{2} }= \frac{28}{ \frac{3+4+6}{12} }= \frac{28}{ \frac{13}{12} }= \frac{28}{1}* \frac{12}{13} = \frac{336}{13} =\ \textgreater \ [/tex]

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