Question

impartiti numarul 268 in parti invers proportionale cu numerele : 3,8,10

Answer 1

Fie 268=a+b+c
3*a=8*b=10*c
b=3*a/8
c=3*a/10
a+3*a/8+3*a/10=268. Inmultim cu 40 si obtinem:
40*a+15*a+12*a=10720
67*a=10720
a=10720/67=160
b=3*160/8=60
c=3*160/10=48