Question

Impartiti numarul 350 in parti invers proportionale cu 2 pe 5 si 3 pe 10.Va rog urgent!!!!

Answer 1

a+b=350. 2a/5=3b/10=k, a=5k/2, b=10k/3, 5k/2+10k/3=350, eliminam numitorul, 15k+20k=2100, 35k=2100, k=60. rezulta a=150, b=200

Answer 2

[tex]\Rightarrow\frac{a}{5/2}=\frac{b}{10/3}=...k\;;\;a=5k/2\;si\;b=10k/3\;;\\ \Rightarrow\;a+b=350\Leftrightarrow\;5k/2+10k/3=350\;\;|_{}\cdot6\\ .\;\;\;\;\;\;\;\;\;\;\;15k+20k=2100\;de\; unde\;k=2100:35=60\;;\\ .\;\;\;\;\;\;\;\;\;\;\;\;a=5*60/2=150\;si\;b=10*60/3=200[/tex]