Question

Impartiti numarul 63 in trei numere invers proportionale cu numerele 2, 3 si 6

Answer 1

x+y+z=63
x,y,z dp cu 2,3,6⇒  2x=3y=6z=k
x=k/2
y=k/3
z=k/6
k/2+k/3+k/6=63  aducem la acelasi numitor
3k+2k+k=378
6k=378
k=63
x=63/2
y=63/3=21
z=63/6=21/2