Question

Impartiti numarul 90 in parti invers proportionale cu 1/3 , 1/5 si 1.7.
AJUTOR VA ROG SA MA AJUTATI DAU CORONITA

Answer 1

a*1/3=b*1/5=c*1/7=k
a*1/3=k,a = k/1/3,a = 3k
b*1/5=k,b=k/1/5,b=5k
c*1/7=k,c=k/1/7,c=7k
a+b+c=90
3k+5k+7k = 90
15k=90
k=90:15
k = 6
a = 3k = 3*6 = 18
b = 5k = 5*6 = 30
c = 7k = 7*6 = 42

Answer 2

a/3 +b/5+c/7 = 90 / 3+5+7
a/3 = 90 /15    a=3  x  6 = 18
b/ 5 = 6        b =5 x 6 = 30
c/ 7 = 6      c = 7 x 6 = 42