Question

Impartiti numarul 90 in parti invers proportionale cu 1 supra 3,1 supra 5,1 supra 7.

Answer 1

{ a, b, c } i.p { 1/3, 1/5, 1/7 }
a x 1/3 = b x 1/5 = c x 1/7 = k
a x 1/3 = k ⇒ a = k / 1/3 = 3k
b x 1/5 = k ⇒ b = k / 1/5 = 5k
c x 1/7 = k ⇒ c = k / 1/7 = 7k
a + b + c = 90
3k + 5k + 7k = 90
15k = 90
k = 90 : 15
k = 6
a = 3 x 6 = 18
b = 5 x 6 = 30
c = 7 x 6 = 42