Question

impartiti numarul natural 80 in trei parti direct proportionale cu numerele 3,4 si respectiv 9

Answer 1

a+b+c=80si a/3=b/4=c/9

Answer 2

$x+y+z = 80$
[tex]x = \frac{80}{3} = 26,(6) [/tex]
$y = \frac{80}{4} = 20$
$z = \frac{80}{9} = 8,(8)$