Question

In 2,28 g de trioxid de azot se gasesc:
a) 0,84 g N
b) 1,44 g O
c) 1,84 g N

Answer 1

Răspuns:

Explicație:

2,28 g N2O3

MN2O3= 2.14 + 3.16=76------>76g/moli

76 g N2O3---------28g N  ---------48gO

2,28g-------------------------xg-------------yg

x=2,28.28 : 76 = 0 84 gN

y=2,28 . 48 : 76=1,44 g O