Question

In 80g de element X cu masa atomica Ax= 40,se afla 96.353*10 la 23 electroni s si 144.528*10 la 23 electroni p.Indicati configuratia electronica si locul in tabelul periodic si identificati elementul X.

Answer 1

Daca la

80 g.. avem... 96,353 x 10la23 e- s

40 g.................. a e- s

=> a = 48,1765 x 10la23

daca la

80 g.. avem... 144,528 x 10la23 e- p

40 g.................. b e- p

=> b = 72,264 x 10la23

n = N / N.A =

n e- s = 48,1765 x 10la23 / 6,022x10la23 = 8 e- s

n e- p = 72,264 x 10la23 / 6,022x10la23 = 12 e- p

=> total e- = 20

=> Z = 20

1s2 2s2 2p6 3s2 3p6 4s2

gr. II. A, per. 4 => X = Ca