Question

In 94 grame de fenol se adauga 200 grame de solutie de NaOH. Calculati %C a solutiei de NaOH

Answer 1

Explicație:

Bună,

C6H5OH+NaOH=C6H5ONa+H2O

M C6H6O=6×12+6+16=94g /mol

m =94 g

nr moli=m/M

nr moli=94/94=1 mol C6H6O

1 mol C6H5OH....1 mol NaOH--->

nr moli NaOH =1 mol

mNaOH=M× nr moli=1×40=40 g

c/100=md/ms--->c=md×100/ms=40×100/200=20%