Question

In ΔABC cu m(∡C) = 90° , AC = 5√3 cm si CB = 5 cm. Calculati AB , m ( ∡A) si m (∡B).

Answer 1

$AB^2=AC^2+BC^2 \\ \\ =(5\sqrt{3})^2+5^2 \\ \\ =75+25=100~cm \\ \\ AB=\sqrt{100}=10~cm$
5 = 10/2
BC = AB/2
m(<A)=30°
m(<B)=60°