Question

In ΔABC se cunosc AB = 15 cm, AC = 18 cm BB' ⊥ AC , B' ∈ AC, CC' ⊥ AB, C' ∈ AB, BB' = 10 cm. Sa se afle CC'. Dau coroana,e urgent.

Answer 1

tr. ABB'

BB'^2=AB•AC'
10^2=15•AC'
AC'= 100/15= 20/3

tr. ACC'
P=AC+CC'+AC'
P= 18+20/3+CC'
P= 30/3+20/3+CC'
P=50/3+CC'
CC'= 50/3