Question

in cate zerouri se termină numărul:1x2x3x4....x74x75

Answer 1

[tex]In\ acest\ caz\ vom\ folosi\ urmatoarea\ formula\ pentru\ numarul\\ de\ zero-uri:\\ {[\frac{n}{5}]+[\frac{n}{25}]+[\frac{n}{125}]+.... ,unde\ [x]\ reprezinta\ partea\ intreaga.}\\ In\ cazul\ nostru\ n=75:\\ {[\frac{75}{5}]+[\frac{75}{25}]+[\frac{75}{125}]+....(\ nu\ mai\ are\ rost\ sa\ continuam)=}\\ {[15]+[3]+0+0+0+....=\\ 15+3=\boxed{18\ zerouri}[/tex]