Question

in cati moli de CaSo4 (suflat de calciu) se afla 8kg de sulf
dau coroana​

Answer 1

Răspuns:

250 mol CaSO₄

Explicație:

8 kg = 8000g

1 mol CaSO₄..........32g S

x mol CaSO₄..........8000g S

x = 8000 : 32 = 250 mol CaSO₄

-Mihai

Answer 2

Răspuns:

m=8kgS=8000gS

MCaSO4 =40+32+4×16=136g/mol

136gCaSO4..........32gS

xgCaSO4..............8000gS

x=136×8000/32=34000gCaSO4

n=m/M=34000136=250moli CaSO4