Question

in ce cantitate de clorura de calciu se afla 80g calciu​

Answer 1

Răspuns:

MCa=40g/mol

MCaCl2=40+2×35,5=111g/mol

40g.................111g

Ca + Cl2 => CaCl2

80g.................xg

x=80×111/40=222gCaCl2