Question

in figura alaturata , dreptele AB║CD , iar MN secanta. Daca AB∩MN={E} , CD∩∩MN={F} si

5*m(∡AEF)=4*m(∡EFD, atunci masura ∡EFD este?

Answer 1

Răspuns:

Explicație pas cu pas:

m(∡AEF)=x

m(∡EFD)=y

x+y=180°

dar 5x=4y

$x=\frac{4y}{5}$

$\frac{4y}{5}+y=180$

4y+5y=180×5

9y=180×5

y=100°

x=80°