Question

In figura alaturata, MN||BC. Demonstrati ca AP=PQ.

Answer 1

[tex] \frac{4}{x-1}= \frac{6}{x+1} \\ 6(x-1)=4(x+1) \\ 6x-6=4x+4 \\ 2x=10 \\ x=5~cm \\ MB=4~cm(1) \\ NP=6~cm(2) \\ Din~(1)~si~(2)=>MN~linie~mijlocie \\ MN~il~imparte~pe~AQ~in~segmente~egale=>AP=PQ[/tex]