Question

in figura alturata ABC este un triughi oarecare. Valoare lui x este egala cu : a) 40⁰ b)15⁰ c)10⁰ d)20⁰​

Answer 1

Răspuns:

3x+4+2x+6+180°-6x+10=180°

-x=(-20)

x = 20

Answer 2

Bună! ✨

·························

ΔABC, Fie B, C, D - puncte coliniare

m(∡ACD)=180°-(6x-10°)=180°-6x+10°=190°-6x

m(∡ACB)=180°-(3x+4°+2x+6°)=180°-5x-10°=170°-5x

190°-6x=170°-5x ⇔ 5x-6x=170°-190° ⇔ -x= -20° ⇒ x=20°

sau

m(∡ACB)=m(∡BCD)-m(∡ACD) ⇒ 6x-10°+170°-5x=180 ⇒

⇒ x+160°=180° => x=20°