Question

In membrul stang puneti paranteze rotunde/patrate/acolade astfel incat scrierea sa fie corecte:
a) 1+3*5=9
b)12+2*1+2+3+4+5+6=54
c)7+5*3+2-2*4-1=26
d)3*6-2*3-1+8=14
e)3*9-2*7-5=17
f)5*4*3-2*1=50
g)`12*6-2+15:5-2=53
h)2*3*4+12:3-1=16
i)41-5*9-4+4:9-5=17
j)8-3*5+13-17-9=30

Answer 1

a) (1+3)*5=9
b){12+[2*(1+2+3+4+5+6)]}=54
c)7+5*(3+2)-2*(4-1)=26
d)3*[6-2*(3-1)]+8=14
e)3*9-2*7-5=17
f)5*(4*3-2*1)=50
g)`12*(6-2)+15:(5-2)=53
h)2*3*4+12:3-1=16
i)41-[5*(9-4)+4:(9-5)]=17
j)(8-3)*5+13-(17-9)=30

Exercitiile e) si h) ori nu le-ai scris corect ori sunt gresit tiparite pt ca indiferent unde punem paranteze nu ne dau  rezultatele
.